Tugas 4 :: Keamanan Informasi : self-generating code

Self-generating code yang dimaksudkan di paper Ken Thompson, Reflections on Trusting Trust adalah suatu code yang jika sudah dicompile kemudian di run akan menghasilkan isi kode tersebut.

Saya mengerjakan tugas ini menggunakan bahasa C.
Programnya:

#include <stdio.h>

void quote(const char *s)
/* This function takes a character string s and prints the
* textual representation of s as it might appear formatted
* in C code. */
{
int i;

printf(”    \””);
for (i=0; s[i]; ++i) {
/* Certain characters are quoted. */
if (s[i] == ‘\\’)
printf(“\\\\”);
else if (s[i] == ‘”‘)
printf(“\\\””);
else if (s[i] == ‘\n’)
printf(“\\n”);
/* Others are just printed as such. */
else
printf(“%c”, s[i]);
/* Also insert occasional line breaks. */
if (i % 48 == 47)
printf(“\”\n    \””);
}
printf(“\””);
}

/* What follows is a string representation of the program code,
* from beginning to end (formatted as per the quote() function
* above), except that the string _itself_ is coded as two
* consecutive ‘@’ characters. */
const char progdata[] =
“/* A simple quine (self-printing program), in st”
“andard C. */\n\n/* Note: in designing this quine, ”
“we have tried to make the code clear\n * and read”
“able, not concise and obscure as many quines are”
“, so that\n * the general principle can be made c”
“lear at the expense of length.\n * In a nutshell:”
” use the same data structure (called \”progdata\”\n”
” * below) to output the program code (which it r”
“epresents) and its own\n * textual representation”
“. */\n\n#include <stdio.h>\n\nvoid quote(const char ”
“*s)\n     /* This function takes a character stri”
“ng s and prints the\n      * textual representati”
“on of s as it might appear formatted\n      * in ”
“C code. */\n{\n    int i;\n\n    printf(\”    \\\”\”);\n ”
”   for (i=0; s[i]; ++i) {\n        /* Certain cha”
“racters are quoted. */\n        if (s[i] == ‘\\\\’)”
“\n            printf(\”\\\\\\\\\”);\n        else if (s[”
“i] == ‘\”‘)\n            printf(\”\\\\\\\”\”);\n        e”
“lse if (s[i] == ‘\\n’)\n            printf(\”\\\\n\”);”
“\n        /* Others are just printed as such. */\n”
”        else\n            printf(\”%c\”, s[i]);\n   ”
”     /* Also insert occasional line breaks. */\n ”
”       if (i % 48 == 47)\n            printf(\”\\\”\\”
“n    \\\”\”);\n    }\n    printf(\”\\\”\”);\n}\n\n/* What fo”
“llows is a string representation of the program ”
“code,\n * from beginning to end (formatted as per”
” the quote() function\n * above), except that the”
” string _itself_ is coded as two\n * consecutive ”
“‘@’ characters. */\nconst char progdata[] =\n@@;\n\n”
“int main(void)\n     /* The program itself… */\n”
“{\n    int i;\n\n    /* Print the program code, cha”
“racter by character. */\n    for (i=0; progdata[i”
“]; ++i) {\n        if (progdata[i] == ‘@’ && prog”
“data[i+1] == ‘@’)\n            /* We encounter tw”
“o ‘@’ signs, so we must print the quoted\n       ”
”      * form of the program code. */\n        {\n ”
”           quote(progdata);    /* Quote all. */\n”
”            i++;                /* Skip second ‘”
“@’. */\n        } else\n            printf(\”%c\”, p”
“rogdata[i]);  /* Print character. */\n    }\n    r”
“eturn 0;\n}\n”;

int main(void)
/* The program itself… */
{
int i;

/* Print the program code, character by character. */
for (i=0; progdata[i]; ++i) {
if (progdata[i] == ‘@’ && progdata[i+1] == ‘@’)
/* We encounter two ‘@’ signs, so we must print the quoted
* form of the program code. */
{
quote(progdata);    /* Quote all. */
i++;                /* Skip second ‘@’. */
} else
printf(“%c”, progdata[i]);  /* Print character. */
}
return 0;
}

PrintScreen Outputnya:

jadi hasil output yang dihasilkan sama persis seperti code yang ada di dalam program yang dibuat.